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What is std::move(), and when should it be used?

  1. What is it?
  2. What does it do?
  3. When should it be used?

Good links are appreciated.

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Basilevs Avatar asked Aug 05 '10 09:08

Basilevs


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When should you use std :: move?

std::move() is a function used to convert an lvalue reference into the rvalue reference. Used to move the resources from a source object i.e. for efficient transfer of resources from one object to another. std::move() is defined in the <utility> header.

What does move () do in C++?

std::move in C++Moves the elements in the range [first,last] into the range beginning at result. The value of the elements in the [first,last] is transferred to the elements pointed by result. After the call, the elements in the range [first,last] are left in an unspecified but valid state.

What is the difference between std :: forward and std :: move?

std::move takes an object and casts it as an rvalue reference, which indicates that resources can be "stolen" from this object. std::forward has a single use-case: to cast a templated function parameter of type forwarding reference ( T&& ) to the value category ( lvalue or rvalue ) the caller used to pass it.

Where is std :: move defined?

In C++11, std::move is a standard library function that casts (using static_cast) its argument into an r-value reference, so that move semantics can be invoked. Thus, we can use std::move to cast an l-value into a type that will prefer being moved over being copied. std::move is defined in the utility header.


1 Answers

1. "What is it?"

While std::move() is technically a function - I would say it isn't really a function. It's sort of a converter between ways the compiler considers an expression's value.

2. "What does it do?"

The first thing to note is that std::move() doesn't actually move anything. It changes an expression from being an lvalue (such as a named variable) to being an xvalue. An xvalue tells the compiler:

You can plunder me, move anything I'm holding and use it elsewhere (since I'm going to be destroyed soon anyway)".

in other words, when you use std::move(x), you're allowing the compiler to cannibalize x. Thus if x has, say, its own buffer in memory - after std::move()ing the compiler can have another object own it instead.

You can also move from a prvalue (such as a temporary you're passing around), but this is rarely useful.

3. "When should it be used?"

Another way to ask this question is "What would I cannibalize an existing object's resources for?" well, if you're writing application code, you would probably not be messing around a lot with temporary objects created by the compiler. So mainly you would do this in places like constructors, operator methods, standard-library-algorithm-like functions etc. where objects get created and destroyed automagically a lot. Of course, that's just a rule of thumb.

A typical use is 'moving' resources from one object to another instead of copying. @Guillaume links to this page which has a straightforward short example: swapping two objects with less copying.

template <class T> swap(T& a, T& b) {     T tmp(a);   // we now have two copies of a     a = b;      // we now have two copies of b (+ discarded a copy of a)     b = tmp;    // we now have two copies of tmp (+ discarded a copy of b) } 

using move allows you to swap the resources instead of copying them around:

template <class T> swap(T& a, T& b) {     T tmp(std::move(a));     a = std::move(b);        b = std::move(tmp); } 

Think of what happens when T is, say, vector<int> of size n. In the first version you read and write 3*n elements, in the second version you basically read and write just the 3 pointers to the vectors' buffers, plus the 3 buffers' sizes. Of course, class T needs to know how to do the moving; your class should have a move-assignment operator and a move-constructor for class T for this to work.

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einpoklum Avatar answered Sep 29 '22 15:09

einpoklum