I saw the following example in the C standard draft (n1570):
$3.14 paragraph 4 : A structure declared as:
struct
{
char a;
int b:5, c:11, :0, d:8;
struct
{
int ee:8;
} e;
}
So, What does :0
mean?
I know what a bit-field is, but :0
is without a name, which I do not understand.
What is the purpose of :0
without any identifier?
Bit Fields in C Language In programming terminology, a bit field is a data structure that allows the programmer to allocate memory to structures and unions in bits in order to utilize computer memory in an efficient manner.
There are a number of reasons you might see an empty bit field. They might be reserved for some future use, such as expanding the existing fields without having to change their offsets.
Bit fields can be used to reduce memory consumption when a program requires a number of integer variables which always will have low values. For example, in many systems storing an integer value requires two bytes (16-bits) of memory; sometimes the values to be stored actually need only one or two bits.
The best way to read a binary number is to start with the right-most digit and work your way left. The power of that first location is zero, meaning the value for that digit, if it's not a zero, is two to the power of zero, or one. In this case, since the digit is a zero, the value for this place would be zero.
As the document you linked explains right before:
A bit-field and an adjacent non-bit-field member are in separate memory locations. The same applies to two bit-fields, if one is declared inside a nested structure declaration and the other is not, or if the two are separated by a zero-length bit-field declaration, or if they are separated by a non-bit-field member declaration
It is a way to tell the compiler that b
and c
can/will be in the same memory location whereas d
must be separate from them and can be modified concurrently to b/c
First of all, let's see chapter §6.7.2.1, Structure and union specifiers, P11. It says,
An implementation may allocate any addressable storage unit large enough to hold a bitfield. If enough space remains, a bit-field that immediately follows another bit-field in a structure shall be packed into adjacent bits of the same unit. [...]
But, in case, we explicitly want two consecutive bit-field members, which "might be" packed into a single memory location to reside on separate memory location (i.e., addressable storage unit ), the above is the way to force it.
The next paragraph, P12, mentions,
A bit-field declaration with no declarator, but only a colon and a width, indicates an unnamed bit-field.126) As a special case, a bit-field structure member with a width of 0 indicates that no further bit-field is to be packed into the unit in which the previous bit-field, if any, was placed.
following your example, this makes sure that the two bit-field members surrounding the :0
will be residing in separate memory location (not inside a single addressable storage unit, even if sufficient memory remains to pack them into one). This has the similar effect of having a non-bit-field member in between two bit-fields, to force the separation of the memory location.
Quoting C11
, chapter §3.14, NOTE 2
(emphasis mine)
A bit-field and an adjacent non-bit-field member are in separate memory locations. The same applies to two bit-fields, if one is declared inside a nested structure declaration and the other is not, or if the two are separated by a zero-length bit-field declaration, or if they are separated by a non-bit-field member declaration.
Also, regarding the usage ("why it is needed" part)
[...] The bit-fields
b
andc
cannot be concurrently modified, butb
anda
, for example, can be.
Addendum:
Regarding the concurrency part, from NOTE 1
Two threads of execution can update and access separate memory locations without interfering with each other.
and, from chapter §5.1.2.4/P1,
Under a hosted implementation, a program can have more than one thread of execution (or thread) running concurrently. [...]
So, this is a theoretically viable option, as per the standard.
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