Variables in bash seq replacement ({1..10}) [duplicate]

Question

Is it possible to do something like this:

start=1 end=10 echo {$start..$end} # Ouput: {1..10} # Expected: 1 2 3 ... 10 (echo {1..10}) 

Answer 1

In bash, brace expansion happens before variable expansion, so this is not directly possible.

Instead, use an arithmetic for loop:

start=1 end=10 for ((i=start; i<=end; i++)) do    echo "i: $i" done 

OUTPUT

i: 1 i: 2 i: 3 i: 4 i: 5 i: 6 i: 7 i: 8 i: 9 i: 10 

Answer 2

You should consider using seq(1). You can also use eval:

eval echo {$start..$end} 

And here is seq

seq -s' ' $start $end