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How to UNCOMMENT a line that contains a specific string using Sed?

Tags:

bash

sed

awk

People also ask

How do you uncomment a line in a script?

You can “uncomment a line” in a configuration file by removing the # at the start of the line. Or, to “comment out” a line, add a # character to the start of the line. (Note that some languages have different comment formats, so this may not be true if you're working with a source code file.)

How do you use sed on a specific line?

Just add the line number before: sed '<line number>s/<search pattern>/<replacement string>/ . Note I use . bak after the -i flag. This will perform the change in file itself but also will create a file.

How do I uncomment a line in Linux?

Press CTRL + V to enable visual block mode. Move down and select the lines till you want to uncomment. press x and it will uncomment all the selected lines at once.


Yes, to comment line containing specific string with sed, simply do:

sed -i '/<pattern>/s/^/#/g' file

And to uncomment it:

sed -i '/<pattern>/s/^#//g' file

In your case:

sed -i '/2001/s/^/#/g' file    (to comment out)
sed -i '/2001/s/^#//g' file    (to uncomment)

Option "g" at the end means global change. If you want to change only a single instance of pattern, just skip this.


Try this sed command,

sed -i '/^#.* 2001 /s/^#//' file

To complement @Avinash Raj's helpful answer with a more generic, POSIX-compliant solution.

  • Toggles commenting of lines that match a specifiable string that must occur as a separate word anywhere on the line.
  • The comment character (string) is also specifiable.

Note that the solution is awk-based, because a robust portable solution with sed is virtually impossible due to the limitations of POSIX' basic regular expressions.

awk -v commentId='#' -v word='2001' '
  $0 ~ "(^|[[:punct:][:space:]])" word "($|[[:punct:][:space:]])" { 
    if (match($0, "^[[:space:]]*" commentId))
      $0 = substr($0, RSTART + RLENGTH)
    else
      $0 = commentId $0
  } 
  { print }
  ' file > tmpfile.$$ && mv tmpfile.$$ file
  • (^|[[:punct:][:space:]]) and ($|[[:punct:][:space:]]) are the POSIX extended regex equivalents of the \< and \> word-boundary assertions known from other regex dialects.
  • Whitespace after the comment char is preserved, but not before it.
  • When prepending the comment char to a line, it is directly prepended, without whitespace.
  • Thus, if you only toggle comments with this solution, all whitespace is preserved.
  • POSIX awk doesn't offer in-place updating (neither does POSIX sed, incidentally), hence the output is first captured in a temporary file and that file then replaces the original on success.

Quick example of how to comment and uncomment a line in a file.

Sample file :

umask 027
TMOUT=600

Lets now backup the file (just for laughs) and comment out and un comment:

# backup file (because we should always do this)
cp /etc/bash.bashrc /etc/bash.bashrc.$(date '+%Y-%m-%d,%H:%M:%S')

# original: TMOUT=600   , result :# TMOUT=600
sed -i '/[^#]/ s/\(^TMOUT=600.*$\)/#\ \1/' /etc/bash.bashrc

# original # TMOUT=600   ,result :TMOUT=600
sed -i '/^#.*TMOUT=600.*$/s/^#\ //' /etc/bash.bashrc