I have a problem concerning storing the output of a command inside a variable within a bash script.
I know in general there are two ways to do this
either
foo=$(bar) # or foo=`bar`
but for the Java version query, this doesn't seem to work.
I did:
version=$(java --version)
This doesn't store the value inside the var. It even still prints it, which really shouldn't be the case.
I also tried redirecting output to a file but this also fails.
Here are the different ways to store the output of a command in shell script. You can also use these commands on terminal to store command outputs in shell variables. variable_name=$(command) variable_name=$(command [option ...] arg1 arg2 ...) OR variable_name=`command` variable_name=`command [option ...]
the shortcut is Ctrl + Shift + S ; it allows the output to be saved as a text file, or as HTML including colors!
The echo command is useful to display the variable's output especially when you know the content of a variable will not cause any issue.
version=$(java -version 2>&1)
The version param only takes one dash, and if you redirect stderr, which is, where the message is written to, you'll get the desired result.
As a sidenote, using two dashes is an inofficial standard on Unix like systems, but since Java tries to be almost identical over different platforms, it violates the Unix/Linux-expectations and behaves the same in this regard as on windows, and as I suspect, on Mac OS.
That is because java -version
writes to stderr
and not stdout
. You should use:
version=$(java -version 2>&1)
In order to redirect stderr
to stdout
.
You can see it by running the following 2 commands:
java -version > /dev/null java -version 2> /dev/null
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