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COMPANY_NAME=`cat file.txt | grep "company_name" | cut -d '=' -f 2` outputs something like this
"Abc Inc"; What I want to do is I want to remove the trailing ";" as well. How can i do that? I am a beginner to bash. Any thoughts or suggestions would be helpful.
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Two Bash parameter expansion techniques can help us to remove the last character from a variable: Substring expansion – ${VAR:offset:length} Removing matching suffix pattern – ${VAR%word}
The tr command (short for translate) is used to translate, squeeze, and delete characters from a string. You can also use tr to remove characters from a string.
The sed is a free and open-source stream editor for Linux, macOS, *BSD, and Unix-like systems. It is perfect for removing/deleting the last character and perform other options on your files or shell variables.
In this method, you have to use the rev command. The rev command is used to reverse the line of string characterwise. Here, the rev command will reverse the string, and then the -c option will remove the first character. After this, the rev command will reverse the string again and you will get your output.
This will remove the last character contained in your COMPANY_NAME var regardless if it is or not a semicolon:
echo "$COMPANY_NAME" | rev | cut -c 2- | rev If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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