There are two cases where typedef
confuses me when it comes to extern template declaration
and explicit template instantiation
.
To illustrate the two see below 2 example code snippets.
Consider following example (Case 1):
// suppose following code in some cpp file
template <typename T>
struct example
{
T value;
};
// valid typedefs
typedef example<int> int_example;
typedef example<std::string> string_example;
// explicit instantiation using above typedefs
template class int_example; // -> compile time error
template class string_example; // -> compile time error
// instead we need to use type names
template class example<int>; // -> OK
template class example<std::string>; // -> OK
// QUESTION 1: Why does this work however? is this valid code?
typedef std::string type_string;
template class example<type_string>;
Why does the template class example<type_string>
work with typedef ? and why is it valid while template class string_example
is not?
Consider following example (Case 2):
// suppose following code is in some header file
template <typename T>
struct example
{
T value;
};
// valid typedefs
typedef std::string type_string;
typedef example<type_string> string_example;
// Explicit instantiation declaration
// QUESTION 2: Is this valid code? if not why not?
extern template string_example; // -> at least this compiles, but is it OK?
As questioned in the comment above, is it valid to use typedef in extern template declaration
, like in the example above, and why does this compile unlike the Case1 where it does not.
I've read about similar cases but none gives the detailed answer to above 2 questions. detailed elaboration is very much appreciated!
template class int_example;
is not legal. From the C++11 Stanard:
14.7.2 Explicit instantiation
2 The syntax for explicit instantiation is:
explicit-instantiation:
extern
opttemplate
declarationThere are two forms of explicit instantiation: an explicit instantiation definition and an explicit instantiation declaration. An explicit instantiation declaration begins with the
extern
keyword.3 If the explicit instantiation is for a class or member class, the elaborated-type-specifier in the declaration shall include a simple-template-id.
simple-template-id is defined in Section A.12 Templates as:
simple-template-id:
template-name<
template-argument-listopt>
int_example
does not qualify as a simple-template-id.example<int>
does qualify as a simple-template-id.
However, by that logic,
extern template string_example;
is not legal either. I don't know how it works for you. I got the following error when I tried to compile such a line in g++ 4.9.3.
socc.cc:15:31: error: expected unqualified-id before ‘;’ token
extern template string_example; // -> compile time error
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