template<class T> struct A {
typedef int Int;
A::Int b; // Line 1 (fails)
Int c; // Line 2 (compiles)
};
int main(){
A<int> x;
x.c = 13;
}
Errors
error: ISO C++ forbids declaration of ‘Int’ with no type
error: extra qualification ‘A<T>::’ on member ‘Int’
error: expected ‘;’ before ‘b’
Line 1 fails but Line 2 compiles. Why?
You need a typename
typename A::Int b;
The typename
keyword is required because the member is referred to using a qualified name A::Int
.
Int c
is fine because no qualified name is used in that case.
14.6/6
Within the definition of a class template or within the definition of a member of a class template, the keyword typename is not required when referring to the unqualified name of a previously declared member of the class template that declares a type. The keyword typename shall always be specified when the member is referred to using a qualified name, even if the qualifier is simply the class template name.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With