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Get current QNetworkInterface active and connected to the internet

I would like get the current network interface active and connected to the internet.

Actually, I can check if a network is up and if is not a loop back network.

  foreach(QNetworkInterface interface, QNetworkInterface::allInterfaces())
    {
        if (interface.flags().testFlag(QNetworkInterface::IsUp) && !interface.flags().testFlag(QNetworkInterface::IsLoopBack))
            foreach (QNetworkAddressEntry entry, interface.addressEntries())
            {
            if ( interface.hardwareAddress() != "00:00:00:00:00:00" && entry.ip().toString().contains("."))
                items << interface.name() + " "+ entry.ip().toString() +" " + interface.hardwareAddress();
        }

Results:

"en1 3.3.3.52 D4:9A:20:61:1F:72" 
"vmnet1 192.168.169.1 00:50:56:C0:00:01" 
"vmnet8 192.168.210.1 00:50:56:C0:00:08"

In fact it works but I found also VM interfaces. And I want to only select WLAN interfaces and Ethernet interfaces.

like image 245
menkel Avatar asked Dec 22 '22 15:12

menkel


1 Answers

Sorry to revive an old question, but I was just pondering this myself and came up with a solution:

QList<QString> possibleMatches;
QList<QNetworkInterface> ifaces = QNetworkInterface::allInterfaces();
if ( !ifaces.isEmpty() )
{
  for(int i=0; i < ifaces.size(); i++)
  {
    unsigned int flags = ifaces[i].flags();
    bool isLoopback = (bool)(flags & QNetworkInterface::IsLoopBack);
    bool isP2P = (bool)(flags & QNetworkInterface::IsPointToPoint);
    bool isRunning = (bool)(flags & QNetworkInterface::IsRunning);

    // If this interface isn't running, we don't care about it
    if ( !isRunning ) continue;
    // We only want valid interfaces that aren't loopback/virtual and not point to point
    if ( !ifaces[i].isValid() || isLoopback || isP2P ) continue;
    QList<QHostAddress> addresses = ifaces[i].allAddresses();
    for(int a=0; a < addresses.size(); a++)
    {
      // Ignore local host
      if ( addresses[a] == QHostAddress::LocalHost ) continue;

      // Ignore non-ipv4 addresses
      if ( !addresses[a].toIPv4Address() ) continue;

      QString ip = addresses[a].toString();
      if ( ip.isEmpty() ) continue;
      bool foundMatch = false;
      for (int j=0; j < possibleMatches.size(); j++) if ( ip == possibleMatches[j] ) { foundMatch = true; break; }
      if ( !foundMatch ) { possibleMatches.push_back( ip ); qDebug() << "possible address: " << ifaces[i].humanReadableName() << "->" << ip; }
    }
  }
}
// Now you can peek through the entries in possibleMatches
// With VMWare installed, I get two entries, and the first one is the correct one.
// If you wanted to test which one has internet connectivity, try creating a tcp
// connection to a known internet service (e.g. google.com) and if the connection
// is successful, check the following on the tcp connection
/*
if ( socket->localAddress().toIPv4Address() )
{
  for(int c=0; c < possibleMatches.size(); c++) if ( socket->localAddress().toString() == possibleMatches[c] ) { qDebug() << "Your LAN IP:" << possibleMatches[c]; }
}
*/

You may want to make it a little more robust, so the code could keep track of both the interface and the ip address, but that may be unnecessary, since I'm pretty sure an interface can't hold more than one ip address, and no two interfaces can have the same IP address (correct me if I'm wrong on that assumption).

like image 194
OzBarry Avatar answered Dec 24 '22 04:12

OzBarry