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Tools to determine exact location when using ibeacons

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ibeacon

We are working with a Retail client who would like to know if using multiple iBeacons throughout the store would help track a customer's exact location when they are inside the store (of course when they have the client's App installed).

I would like to know what software tools are already available for this purpose?

What is clear is that at the basic level the location of a device can be determined based on it's relative distance from multiple (at least 2) iBeacons. If so, aren't there tools that help with this?

Thanks

like image 757
praveen_r Avatar asked Jan 07 '14 22:01

praveen_r


1 Answers

Obviously this is unlikely to work well due to the inconsistency of the RSSI value (bluetooth signal). However, this is the direction you may want to take it (adapted from lots of stackoverflow research):

Filter RSSI

I use a rolling filter with this whenever the beacons are ranged, using a kFilteringFactor of 0.1:

rollingRssi = (beacon.rssi * kFilteringFactor) + (rollingRssi * (1.0 - kFilteringFactor));

And I use this to get a rolling Accuracy value (in meters). (Thanks David!)

- (double)calculateAccuracyWithRSSI:(double)rssi {
    //formula adapted from David Young's Radius Networks Android iBeacon Code
    if (rssi == 0) {
        return -1.0; // if we cannot determine accuracy, return -1.
    }


    double txPower = -70;
    double ratio = rssi*1.0/txPower;
    if (ratio < 1.0) {
        return pow(ratio,10);
    }
    else {
        double accuracy =  (0.89976) * pow(ratio,7.7095) + 0.111;
        return accuracy;
    }
}

Calculate XY with Trilateration (Beacons 1, 2, and 3 are Beacon subclasses with pre-set X and Y values for location and distance is calculated as above).

float xa = beacon1.locationX;
float ya = beacon1.locationY;
float xb = beacon2.locationX;
float yb = beacon2.locationY;
float xc = beacon3.locationX;
float yc = beacon3.locationY;
float ra = beacon1.filteredDistance;
float rb = beacon2.filteredDistance;
float rc = beacon3.filteredDistance;

float S = (pow(xc, 2.) - pow(xb, 2.) + pow(yc, 2.) - pow(yb, 2.) + pow(rb, 2.) - pow(rc, 2.)) / 2.0;
float T = (pow(xa, 2.) - pow(xb, 2.) + pow(ya, 2.) - pow(yb, 2.) + pow(rb, 2.) - pow(ra, 2.)) / 2.0;
float y = ((T * (xb - xc)) - (S * (xb - xa))) / (((ya - yb) * (xb - xc)) - ((yc - yb) * (xb - xa)));
float x = ((y * (ya - yb)) - T) / (xb - xa);

CGPoint point = CGPointMake(x, y);
return point;
like image 60
rmooney Avatar answered Oct 20 '22 01:10

rmooney