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Swift if statement - multiple conditions separated by commas?

Looking at a Swift example:

if let sourceViewController = sender.sourceViewController as? MealViewController, meal = sourceViewController.meal {
    ...
}

The doc states:

... the code assigns that view controller to the local constant sourceViewController, and checks to see if the meal property on sourceViewController is nil.

Question: Does Swift let you have multiple conditions in your if statement when separated by commas (as in this example with the comma after MealViewController)?

Haven't seen this in the docs.

like image 226
Marcus Leon Avatar asked Feb 16 '16 14:02

Marcus Leon


2 Answers

Yes when you write

if let a = optA, let b = optB, let c = optC {
    
}

Swift does execute the body of the IF only if all the optional bindings are properly completed.

More

Another feature of this technique: the assignments are done in order.

So only if a value is properly assigned to a, Swift tries to assign a value to b. And so on.

This allows you to use the previous defined variable/constant like this

if let a = optA, let b = a.optB {

}

In this case (in second assignment) we are safely using a because we know that if that code is executed, then a has been populated with a valid value.

like image 171
Luca Angeletti Avatar answered Nov 05 '22 01:11

Luca Angeletti


Yes. Swift: Documentation: Language Guide: The Basics: Optional Binding says:

You can include as many optional bindings and Boolean conditions in a single if statement as you need to, separated by commas. If any of the values in the optional bindings are nil or any Boolean condition evaluates to false, the whole if statement’s condition is considered to be false. The following if statements are equivalent:

if let firstNumber = Int("4"), let secondNumber = Int("42"), firstNumber < secondNumber && secondNumber < 100 {
    print("\(firstNumber) < \(secondNumber) < 100")
}   
// Prints "4 < 42 < 100"

if let firstNumber = Int("4") {
    if let secondNumber = Int("42") {
        if firstNumber < secondNumber && secondNumber < 100 {
            print("\(firstNumber) < \(secondNumber) < 100")
        }   
    }   
}   
// Prints "4 < 42 < 100"
like image 27
Joachim Isaksson Avatar answered Nov 05 '22 00:11

Joachim Isaksson