I am using spring data JPA 1.8.2 and trying to get top result. I am using the following method
LearningSession findTopBySourceAndExternalLmsSessionIdAndCourseCodeAndLearnerEnrollmentEnrollmentStatusOrderByIdAsc(String source, String externalLmsSessionId, String courseCode, String enrollmentStatus);
I tried also by removing OrderBy
LearningSession findTopBySourceAndExternalLmsSessionIdAndCourseCodeAndLearnerEnrollmentEnrollmentStatus(String source, String externalLmsSessionId, String courseCode, String enrollmentStatus);
In both cases hibernate is generating the following query. Just use *
for every thing. For order by in the end order by learningse0_.id asc
select TOP ? learningse0_.*
from LearningSession learningse0_
left outer join LearnerEnrollment learnerenr1_ on learningse0_.ENROLLMENT_ID=learnerenr1_.id
where learningse0_.source=?
and learningse0_.externalLmsSessionId=?
and learningse0_.courseCode=?
and learnerenr1_.enrollmentStatus=?
Query is right But I am getting the following exception
Hibernate: select TOP ? learningse0_.id as id1_47_, learningse0_.brandName as brandNam2_47_, learningse0_.courseApprovalId as courseAp3_47_, learningse0_.courseCode as courseCo4_47_, learningse0_.endTime as endTime5_47_, learningse0_.externalLmsSessionId as external6_47_, learningse0_.externalLmsUrl as external7_47_, learningse0_.isCourseMessageDisplay as isCourse8_47_, learningse0_.LANGUAGE_ID as LANGUAG15_47_, learningse0_.LEARNER_ID as LEARNER16_47_, learningse0_.ENROLLMENT_ID as ENROLLM17_47_, learningse0_.learningSessionGuid as learning9_47_, learningse0_.lmsProvider as lmsProv10_47_, learningse0_.redirectUrl as redirec11_47_, learningse0_.source as source12_47_, learningse0_.startTime as startTi13_47_, learningse0_.uniqueUserGuid as uniqueU14_47_ from LearningSession learningse0_ left outer join LearnerEnrollment learnerenr1_ on learningse0_.ENROLLMENT_ID=learnerenr1_.id where learningse0_.source=? and learningse0_.externalLmsSessionId=? and learningse0_.courseCode=? and learnerenr1_.enrollmentStatus=? order by learningse0_.id asc
13:53:47.686 [main] DEBUG org.hibernate.engine.jdbc.spi.SqlExceptionHelper - could not extract ResultSet [n/a]
com.microsoft.sqlserver.jdbc.SQLServerException: Incorrect syntax near '@P0'
com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDatabaseError(SQLServerException.java:216) ~[sqljdbc4-4.0.jar:?]
What I am doing wrong ? I tried First
, Top1
, First1
but result is error. Please help.
Thanks
Not sure if this will work for you, but I ran into the same error and after a lot of digging I figured out that I was using SqlServerDialect in my JpaVendorAdapter, and when I changed it to be more specifically for SqlServer2012 (SqlServerDialect2012) the error went away:
<bean id="jpaVendorAdapter"
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="database" value="SQL_SERVER" />
<property name="databasePlatform" value="org.hibernate.dialect.SQLServer2012Dialect" />
<property name="showSql" value="true" />
</bean>
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With