The JavaScript exception "cyclic object value" occurs when object references were found in JSON. JSON. stringify() doesn't try to solve them and fails accordingly.
The concept of cyclic object is the generalization of that of cyclic sets where Set may be replaced with any other category. Cyclic objects are used in the description of the cyclic structure on Hochschild homology/Hochschild cohomology and hence for the discussion of cyclic homology/cyclic cohomology?.
The circular structure you have is not in JSON, but in the object that you are trying to convert to JSON. Circular structures come from objects which contain something which references the original object. JSON does not have a manner to represent these.
A circular reference occurs if two separate objects pass references to each other. In older browsers circular references were a cause of memory leaks. With improvements in Garbage collection algorithms, which can now handle cycles and cyclic dependencies fine, this is no longer an issue.
Use the second parameter of stringify
, the replacer function, to exclude already serialized objects:
var seen = [];
JSON.stringify(obj, function(key, val) {
if (val != null && typeof val == "object") {
if (seen.indexOf(val) >= 0) {
return;
}
seen.push(val);
}
return val;
});
http://jsfiddle.net/mH6cJ/38/
As correctly pointed out in other comments, this code removes every "seen" object, not only "recursive" ones.
For example, for:
a = {x:1};
obj = [a, a];
the result will be incorrect. If your structure is like this, you might want to use Crockford's decycle or this (simpler) function which just replaces recursive references with nulls:
function decycle(obj, stack = []) {
if (!obj || typeof obj !== 'object')
return obj;
if (stack.includes(obj))
return null;
let s = stack.concat([obj]);
return Array.isArray(obj)
? obj.map(x => decycle(x, s))
: Object.fromEntries(
Object.entries(obj)
.map(([k, v]) => [k, decycle(v, s)]));
}
//
let a = {b: [1, 2, 3]}
a.b.push(a);
console.log(JSON.stringify(decycle(a)))
This is kind of an alternate-answer, but since what a lot of people will come here for is debugging their circular objects and there's not really a great way to do that without pulling in a bunch of code, here goes.
One feature that's not as well-known as JSON.stringify()
is console.table()
. Simply call console.table(whatever);
, and it will log the variable in the console in tabular format, making it rather quite easy and convenient to peruse the variable's contents.
Here is an example of a data structure with cyclic references:
function makeToolshed(){
var nut = {name: 'nut'}, bolt = {name: 'bolt'};
nut.needs = bolt; bolt.needs = nut;
return { nut: nut, bolt: bolt };
}
When you wish to KEEP the cyclic references (restore them when you deserialize, instead of "nuking" them), you have 2 choices, which I'll compare here. First is Douglas Crockford's cycle.js, second is my siberia package. Both work by first "decycling" the object, i.e., constructing another object (without any cyclic references) "containing the same information."
Mr. Crockford goes first:
JSON.decycle(makeToolshed())
As you see, the nested structure of JSON is retained, but there is a new thing, which is objects with the special $ref
property. Let's see how that works.
root = makeToolshed();
[root.bolt === root.nut.needs, root.nut.needs.needs === root.nut]; // retutrns [true,true]
The dollar sign stands for the root. .bolt
having $ref
tells us that .bolt
is an "already seen" object, and the value of that special property (here, the string $["nut"]["needs"]) tells us where, see first ===
above. Likewise for second $ref
and the second ===
above.
Let's use a suitable deep equality test (namely Anders Kaseorg's deepGraphEqual
function from accepted answer to this question) to see if cloning works.
root = makeToolshed();
clone = JSON.retrocycle(JSON.decycle(root));
deepGraphEqual(root, clone) // true
serialized = JSON.stringify(JSON.decycle(root));
clone2 = JSON.retrocycle(JSON.parse(serialized));
deepGraphEqual(root, clone2); // true
Now, siberia:
JSON.Siberia.forestify(makeToolshed())
Siberia does not try to mimic "classic" JSON, no nested structure. The object graph is described in a "flat" manner.
Each node of the object graph is turned into a flat tree (plain key value pair list with integer-only values), which is an entry in .forest.
At index zero, we find the root object, at higher indices, we find the other nodes of the object graph, and negative values (of some key of some tree of the forest) point to the atoms
array, (which is typed via the types array, but we'll skip the typing details here). All terminal nodes are in the atoms table, all non-terminal nodes are in the forest table, and you can see right away how many nodes the object graph has, namely forest.length
. Let's test if it works:
root = makeToolshed();
clone = JSON.Siberia.unforestify(JSON.Siberia.forestify(root));
deepGraphEqual(root, clone); // true
serialized = JSON.Siberia.stringify(JSON.Siberia.forestify(root));
clone2 = JSON.Siberia.unforestify(JSON.Siberia.unstringify(serialized));
deepGraphEqual(root, clone2); // true
will add section later.
I'm currently refactoring the package. Central ideas and algorithms are staying the same, but the new version will be easier to use, the top level API will be different. I will very soon archive siberia and present the refactored version, which I'll call objectgraph. Stay tuned, it will happen this month (August 2020)
ah, and ultra short version for the comparison. For a "pointer", I need as much space as an integer takes, since my "pointers to already seen nodes" (as a matter of fact, to all nodes, already seen or not) are just integers. In Mr. Crockford's version, amount needed to store a "pointer" is bounded only by the size of the object graph. That makes the worst case complexity of Mr. Crockford's version extremely horrible. Mr. Crockford gave us "another Bubblesort". I'm not kidding you. It's that bad. If you don't believe it, there are tests, you can find them starting from the readme of the package (will transform them to be benchmark.js compliant also this month, Aug 2020)
much saver and it shows where an cycle object was.
<script>
var jsonify=function(o){
var seen=[];
var jso=JSON.stringify(o, function(k,v){
if (typeof v =='object') {
if ( !seen.indexOf(v) ) { return '__cycle__'; }
seen.push(v);
} return v;
});
return jso;
};
var obj={
g:{
d:[2,5],
j:2
},
e:10
};
obj.someloopshere = [
obj.g,
obj,
{ a: [ obj.e, obj ] }
];
console.log('jsonify=',jsonify(obj));
</script>
produces
jsonify = {"g":{"d":[2,5],"j":2},"e":10,"someloopshere":[{"d":[2,5],"j":2},"__cycle__",{"a":[10,"__cycle__"]}]}
I've created an GitHub Gist which is able to detect cyclic structures and also de- and encodes them: https://gist.github.com/Hoff97/9842228
To transform just use JSONE.stringify/JSONE.parse. It also de- and encodes functions. If you want to disable this just remove lines 32-48 and 61-85.
var strg = JSONE.stringify(cyclicObject);
var cycObject = JSONE.parse(strg);
You can find an example fiddle here:
http://jsfiddle.net/hoff97/7UYd4/
I create too a github project that can serialize cyclic object and restore the class if you save it in the serializename attribute like a String
var d={}
var a = {b:25,c:6,enfant:d};
d.papa=a;
var b = serializeObjet(a);
assert.equal( b, "{0:{b:25,c:6,enfant:'tab[1]'},1:{papa:'tab[0]'}}" );
var retCaseDep = parseChaine(b)
assert.equal( retCaseDep.b, 25 );
assert.equal( retCaseDep.enfant.papa, retCaseDep );
https://github.com/bormat/serializeStringifyParseCyclicObject
Edit: I have transform my script for NPM https://github.com/bormat/borto_circular_serialize and I have change function names from french to english.
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