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I am trying to retrieve the data from the webpage has the html in below
<div class="someclass"> <p class="name"><a href="#/word/1/">helloworld</a></p> </div> My goal is to parse "#/word/1/" What I did is
target = self.driver.find_element_by_class_name('someclass') print target print target.text print target.get_attribute("css=a@href") print target.tag_name but the output are
<selenium.webdriver.remote.webelement.WebElement object at 0x10bf16210> helloworld None div I tried so many ways , it seems there is no way i can get the content of 'a href' within the targeted class.
I really dont want to do is get the source code of the page, and then do a string searching, that seems dumb....
anyway to get that?
640
The Selenium WebDriver interface has predefined the getText() method, which helps retrieve the text for a specific web element. This method gets the visible, inner text (which is not hidden by CSS) of the web-element.
New Selenium IDE A hyperlink on a page is identified with the anchor tag. To click a link, we can use the link text locator which matches the text enclosed within the anchor tag. We can also use the partial link text locator which matches the text enclosed within the anchor tag partially.
Use the querySelector() method to get an element by an href attribute, e.g. document. querySelector('a[href="https://example.com"]') . The method returns the first element that matches the selector or null if no element with the provided selector exists in the DOM.
As far as I am aware you can get the href by searching through the child elements
div = self.driver.find_element_by_class_name('someclass') div.find_element_by_css_selector('a').get_attribute('href') This should do it for you:
self.driver.find_element_by_css_selector('.someclass a').get_attribute('href') If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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