Using subprocess wait() and poll()

Question

I am trying to write a small app that uses the subprocess module.

My program calls an external Bash command that takes some time to process. During this time, I would like to show the user a series of messages like this:

Processing. Please wait...
The output is foo()

How can I do this using Popen.wait() or Popen.poll(). I have read that I need to use the Popen.returncode, but how I can get it to actively check the state, I don't know.

Answer 1

Both wait() (with timeout specified) and poll() return None if the process has not yet finished, and something different if the process has finished (I think an integer, the exit code, hopefully 0).

Edit:

wait() and poll() have different behaviors:

• wait (without the timeout argument) will block and wait for the process to complete.
• wait with the timeout argument will wait timeout seconds for the process to complete. If it doesn't complete, it will throw the TimeoutExpired exception. If you catch the exception, you're then welcome to go on, or to wait again.
• poll always returns immediately. It effectively does a wait with a timeout of 0, catches any exception, and returns None if the process hasn't completed.
• With either wait or poll, if the process has completed, the popen object's returncode will be set (otherwise it's None - you can check for that as easily as calling wait or poll), and the return value from the function will also be the process's return code.

</Edit>

So I think you should do something like:

while myprocess.poll() is None:     print("Still working...")     # sleep a while 

Be aware that if the bash script creates a lot of output you must use communicate() or something similar to prevent stdout or stderr to become stuffed.