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Can anyone help me out with this problem?
I'm trying to save the awk output into a variable.
variable = `ps -ef | grep "port 10 -" | grep -v "grep port 10 -"| awk '{printf "%s", $12}'` printf "$variable" EDIT: $12 corresponds to a parameter running on that process.
Thanks!
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`awk` command uses '-v' option to define the variable. In this example, the myvar variable is defined in the `awk` command to store the value, “AWK variable” that is printed later. Run the following command from the terminal to check the output.
awk '{ print $2; }' prints the second field of each line. This field happens to be the process ID from the ps aux output. xargs kill -${2:-'TERM'} takes the process IDs from the selected sidekiq processes and feeds them as arguments to a kill command.
The AWK language is useful for manipulation of data files, text retrieval and processing. -F <value> - tells awk what field separator to use. In your case, -F: means that the separator is : (colon). '{print $4}' means print the fourth field (the fields being separated by : ).
If you notice awk 'print $1' prints first word of each line. If you use $3, it will print 3rd word of each line.
#!/bin/bash variable=`ps -ef | grep "port 10 -" | grep -v "grep port 10 -" | awk '{printf $12}'` echo $variable Notice that there's no space after the equal sign.
You can also use $() which allows nesting and is readable.
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