Round to the nearest 500, Python

Question

I'm looking to find a way to round up to the nearest 500.I've been using:

math.ceil(round(8334.00256 + 250, -3))

Whereby I have a value from a scale in a map I am making in ArcGIS. I have the ability to read and write the scale factor (i.e. 1:8334....basically, you set the thousandth and it defaults to a ratio) If the scale factor isn't a factor of 500, I want to round up to the next 500. The math.ceil will round up any decimal value, and the round(n,-3) will round to the nearest thousandth, but I'm struggling to find a way to round to the nearest 500.

Any suggestions? Thanks, Mike

Answer 1

Scale, round, unscale:

round(x / 500.0) * 500.0

Edit: To round up to the next multiple of 500, use the same logic with math.ceil() instead of round():

math.ceil(x / 500.0) * 500.0

Answer 2

I personally find rounding a but messy. I'd rather use:

(x+250)//500*500

// means integer division.

EDIT: Oh, I missed that you round "up". Then maybe

-(-x//500)*500