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I am trying to build a format string with lazy argument, eg I need smth like:
"%s \%s %s" % ('foo', 'bar') # "foo %s bar"
how can i do this?
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Python uses C-style string formatting to create new, formatted strings. The "%" operator is used to format a set of variables enclosed in a "tuple" (a fixed size list), together with a format string, which contains normal text together with "argument specifiers", special symbols like "%s" and "%d".
The format() method formats the specified value(s) and insert them inside the string's placeholder. The placeholder is defined using curly brackets: {}. Read more about the placeholders in the Placeholder section below. The format() method returns the formatted string.
%s is used as a placeholder for string values you want to inject into a formatted string. %d is used as a placeholder for numeric or decimal values. For example (for python 3) print ('%s is %d years old' % ('Joe', 42)) Would output Joe is 42 years old.
A format of . 2f (note the f ) means to display the number with two digits after the decimal point. So the number 1 would display as 1.00 and the number 1.5555 would display as 1.56 .
"%s %%s %s" % ('foo', 'bar')
you need %%
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