Here is the code:
def myfirst_yoursecond(p,q):
a = p.find(" ")
b = q.find(" ")
str_p = p[0:a]
str_q = p[b+1:]
if str_p == str_q:
result = True
else:
result = False
return result
Here is the error:
Traceback (most recent call last):
File "vm_main.py", line 26, in <module>
import main
File "/tmp/vmuser_ssgopfskde/main.py", line 22
result = False
^
IndentationError: expected an indented block
What's wrong with my code?
However, since the next non-empty line it reads is the elif line, and that line's parent is the def line, the if line has no children, and Python reports that it expected some indented lines. To fix this, either place at least one line of code as the if 's child, or remove the if entirely.
Indentation refers to the spaces at the beginning of a code line. Where in other programming languages the indentation in code is for readability only, the indentation in Python is very important. Python uses indentation to indicate a block of code.
You've mixed tabs and spaces. This can lead to some confusing errors.
I'd suggest using only tabs or only spaces for indentation.
Using only spaces is generally the easier choice. Most editors have an option for automatically converting tabs to spaces. If your editor has this option, turn it on.
As an aside, your code is more verbose than it needs to be. Instead of this:
if str_p == str_q:
result = True
else:
result = False
return result
Just do this:
return str_p == str_q
You also appear to have a bug on this line:
str_q = p[b+1:]
I'll leave you to figure out what the error is.
This error also occurs if you have a block with no statements in it
For example:
def my_function():
for i in range(1,10):
def say_hello():
return "hello"
Notice that the for
block is empty. You can use the pass statement if you want to test the remaining code in the module.
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