I have an XML in the following format:
<Accounts>
<Account Number="1" DebitAmount="1000" Amount="2827561.95" />
<Account Number="225" DebitAmount="2000" Amount="12312.00" />
<Account Number="236" DebitAmount="London" Amount="457656.00" />
<Account Number="225" DebitAmount="London" Amount="23462.40" />
<Account Number="236" DebitAmount="Bangalore" Amount="2345345.00" />
</Accounts>
How do I retreive the unique Account Numbers using Xpath? ie, I want to get the values 1, 225 and 236.
This is what I did:(I'm using Delphi 2007...)
Const XmlStr =
' <Accounts>
<Account Number="1" DebitAmount="1000" Amount="2827561.95" />
<Account Number="225" DebitAmount="2000" Amount="12312.00" />
<Account Number="236" DebitAmount="London" Amount="457656.00" />
<Account Number="225" DebitAmount="London" Amount="23462.40" />
<Account Number="236" DebitAmount="Bangalore" Amount="2345345.00" />
</Accounts>';
function GetAccountNumbers:TList;
Var
XMLDOMDocument : IXMLDOMDocument;
accounts : IXMLDOMNodeList;
accountdetail :IXMLDOMNode;
i:Integer
list :TList
begin
Result:=TList.Create;
XMLDOMDocument:=CoDOMDocument.Create;
XMLDOMDocument.loadXML(XmlStr);
accounts:= XMLDOMDocument.SelectNodes(''./Accounts
/Account[not(@Number=preceding-sibling/ Account /@Number)]');
for i := 0 to accountdetails.length - 1 do begin
accountdetail := accountdetails.item[i];
//omitting the "<>nil" checks...
list.Add(accountdetail.attributes.getNamedItem('Number').Nodevalue;
end;
end;
But this returns no nodes(accountdetails.length=0). Please let me know what I am missing here.
Thanks,
Pradeep
We can use distinct-values function which is available in XPath 2.0 for finding the unique values. The fn:distinct-values function returns a sequence of unique atomic values from $arg . Values are compared based on their typed value.
XPath uses path expressions to select nodes or node-sets in an XML document. These path expressions look very much like the expressions you see when you work with a traditional computer file system. XPath expressions can be used in JavaScript, Java, XML Schema, PHP, Python, C and C++, and lots of other languages.
XPath doesn't allow projection of new types. It can only return collections of nodes from the tree, whereas LINQ to XML can execute a query and project an object graph or an XML tree in a new shape. LINQ to XML queries can do much more than XPath expressions.
It seems the version of the MSXML from Delphi 2007 doesn't support XPath axis. So if you decide to use the following code, import either Microsoft XML, v3.0
or the Microsoft XML, v6.0
type library first and then try this:
unit Unit1;
interface
uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, StdCtrls, MSXML2_TLB;
type
TForm1 = class(TForm)
Button1: TButton;
procedure Button1Click(Sender: TObject);
private
{ Private declarations }
public
{ Public declarations }
end;
var
Form1: TForm1;
implementation
{$R *.dfm}
const
XMLString =
'<Accounts>' +
'<Account Number="1" DebitAmount="1000" Amount="2827561.95"/>' +
'<Account Number="225" DebitAmount="2000" Amount="12312.00"/>' +
'<Account Number="236" DebitAmount="London" Amount="457656.00"/>' +
'<Account Number="225" DebitAmount="London" Amount="23462.40"/>' +
'<Account Number="236" DebitAmount="Bangalore" Amount="2345345.00"/>' +
'</Accounts>';
type
TIntegerArray = array of Integer;
function GetAccountNumbers(const AXMLString: string): TIntegerArray;
var
I: Integer;
XMLDOMNodeList: IXMLDOMNodeList;
XMLDOMDocument: IXMLDOMDocument3;
begin
XMLDOMDocument := CoDOMDocument60.Create;
if Assigned(XMLDOMDocument) and XMLDOMDocument.loadXML(AXMLString) then
begin
XMLDOMNodeList := XMLDOMDocument.selectNodes('/Accounts/Account[not(@Number=preceding-sibling::Account/@Number)]/@Number');
SetLength(Result, XMLDOMNodeList.length);
for I := 0 to XMLDOMNodeList.length - 1 do
Result[I] := XMLDOMNodeList.item[I].nodeValue;
end;
end;
procedure TForm1.Button1Click(Sender: TObject);
var
S: string;
I: Integer;
IntegerArray: TIntegerArray;
begin
S := 'Account numbers: ';
IntegerArray := GetAccountNumbers(XMLString);
for I := 0 to Length(IntegerArray) - 1 do
S := S + IntToStr(IntegerArray[I]) + ', ';
Delete(S, Length(S) - 1, 2);
ShowMessage(S);
end;
end.
Don't understand exactly what do you want to achieve. Maybe this?
'/Accounts/Account[not(@Number=preceding-sibling::node()/@Number)]/@Number'
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