Quickest way to convert XML to JSON in Java [closed]

Question

What are some good tools for quickly and easily converting XML to JSON in Java?

Answer 1

JSON in Java has some great resources.

Maven dependency:

<dependency>   <groupId>org.json</groupId>   <artifactId>json</artifactId>   <version>20180813</version> </dependency> 

XML.java is the class you're looking for:

import org.json.JSONObject; import org.json.XML; import org.json.JSONException;  public class Main {      public static int PRETTY_PRINT_INDENT_FACTOR = 4;     public static String TEST_XML_STRING =         "<?xml version=\"1.0\" ?><test attrib=\"moretest\">Turn this to JSON</test>";      public static void main(String[] args) {         try {             JSONObject xmlJSONObj = XML.toJSONObject(TEST_XML_STRING);             String jsonPrettyPrintString = xmlJSONObj.toString(PRETTY_PRINT_INDENT_FACTOR);             System.out.println(jsonPrettyPrintString);         } catch (JSONException je) {             System.out.println(je.toString());         }     } } 

Output is:

{"test": {     "attrib": "moretest",     "content": "Turn this to JSON" }} 

Answer 2

To convert XML File in to JSON include the following dependency

<dependency>     <groupId>org.json</groupId>     <artifactId>json</artifactId>     <version>20140107</version> </dependency> 

and you can Download Jar from Maven Repository here. Then implement as:

String soapmessageString = "<xml>yourStringURLorFILE</xml>"; JSONObject soapDatainJsonObject = XML.toJSONObject(soapmessageString); System.out.println(soapDatainJsonObject);