PHP - cannot use a scalar as an array warning

Question

I have the following code:

 $final = array();     foreach ($words as $word) {         $query = "SELECT Something";         $result = $this->_db->fetchAll($query, "%".$word."%");         foreach ($result as $row)         {             $id = $row['page_id'];             if (!empty($final[$id][0]))             {                 $final[$id][0] = $final[$id][0]+3;             }             else             {                 $final[$id][0] = 3;                 $final[$id]['link'] = "/".$row['permalink'];                 $final[$id]['title'] = $row['title'];             }         }      } 

The code SEEMS to work fine, but I get this warning:

Warning: Cannot use a scalar value as an array in line X, Y, Z (the line with: $final[$id][0] = 3, and the next 2). 

Can anyone tell me how to fix this?

Answer 1

You need to set$final[$id] to an array before adding elements to it. Intiialize it with either

$final[$id] = array(); $final[$id][0] = 3; $final[$id]['link'] = "/".$row['permalink']; $final[$id]['title'] = $row['title']; 

or

$final[$id] = array(0 => 3); $final[$id]['link'] = "/".$row['permalink']; $final[$id]['title'] = $row['title']; 

Answer 2

A bit late, but to anyone who is wondering why they are getting the "Warning: Cannot use a scalar value as an array" message;

the reason is because somewhere you have first declared your variable with a normal integer or string and then later you are trying to turn it into an array.

hope that helps