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If I pass any number of arguments to a shell script that invokes a Java program internally, how can I pass second argument onwards to the Java program except the first?
./my_script.sh a b c d ....
#my_script.sh ... java MyApp b c d ... 
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To pass multiple arguments to a shell script you simply add them to the command line: # somescript arg1 arg2 arg3 arg4 arg5 … To pass multiple arguments to a shell script you simply add them to the command line: # somescript arg1 arg2 arg3 arg4 arg5 …
To invoke a function, simply use the function name as a command. To pass parameters to the function, add space separated arguments like other commands. The passed parameters can be accessed inside the function using the standard positional variables i.e. $0, $1, $2, $3 etc.
bash [filename] runs the commands saved in a file. $@ refers to all of a shell script's command-line arguments. $1 , $2 , etc., refer to the first command-line argument, the second command-line argument, etc. Place variables in quotes if the values might have spaces in them.
First use shift to "consume" the first argument, then pass "$@", i.e., the list of remaining arguments:
#my_script.sh ... shift java MyApp "$@" If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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