How to start multiple processes in Bash

Question

I want to start 100 processes in bash, but the for statement doesn't seems to like the & symbol and I'm getting a syntax error, here is what I have so far:

echo "Spawning 100 processes" for i in {1..100} do     ./my_script.py & done 

EDIT: I was copypasting this code, that's why the & char was illegal.

Answer 1

echo "Spawning 100 processes" for i in {1..100} ; do     ( ./my_script & ) ; done