bash getopts with multiple and mandatory options

Question

Is it possible to use getopts to process multiple options together? For example, myscript -iR or myscript -irv.

Also, I have a situation where based on a condition script would need mandatory option. For example, if argument to script is a directory, I will need to specify -R or -r option along with any other options (myscript -iR mydir or myscript -ir mydir or myscript -i -r mydir or myscript -i -R mydir), in case of file only -i is sufficient (myscript -i myfile).

I tried to search but didn't get any answers.

Answer 1

You can concatenate the options you provide and getopts will separate them. In your case statement you will handle each option individually.

You can set a flag when options are seen and check to make sure mandatory "options" (!) are present after the getopts loop has completed.

Here is an example:

#!/bin/bash rflag=false small_r=false big_r=false  usage () { echo "How to use"; }  options=':ij:rRvh' while getopts $options option do     case "$option" in         i  ) i_func;;         j  ) j_arg=$OPTARG;;         r  ) rflag=true; small_r=true;;         R  ) rflag=true; big_r=true;;         v  ) v_func; other_func;;         h  ) usage; exit;;         \? ) echo "Unknown option: -$OPTARG" >&2; exit 1;;         :  ) echo "Missing option argument for -$OPTARG" >&2; exit 1;;         *  ) echo "Unimplemented option: -$OPTARG" >&2; exit 1;;     esac done  if ((OPTIND == 1)) then     echo "No options specified" fi  shift $((OPTIND - 1))  if (($# == 0)) then     echo "No positional arguments specified" fi  if ! $rflag && [[ -d $1 ]] then     echo "-r or -R must be included when a directory is specified" >&2     exit 1 fi 

This represents a complete reference implementation of a getopts function, but is only a sketch of a larger script.