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Does the C++ standard guarantee that the call
c = std::min(f(x), g(x));
evaluates the functions f and g only once?
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The many variations of the min , max , and minmax functions apply to values and initializer lists. These functions need the header <algorithm> . Nearly the same holds for the functions std::move , std::forward and std::swap . You can apply them to arbitrary values.
std::max is defined in the header file <algorithm> and is used to find out the largest of the number passed to it. It returns the first of them, if there are more than one.
std::min and std::max are constexpr in C++14, which obviously means there isn't a good reason (these days) not to have them constexpr.
The max() function returns the greater of two values. The max() function is for C programs only. For C++ programs, use the __max() macro.
Yes. Since std::min is a function, f(x) and g(x) will be evaluated only once. And returned values won't be copied. See the prototype of the function :
template<typename T>
const T& min ( const T& a, const T& b );
It is a clear difference with preprocessor-genuinely-defined min macro :
#define MIN(A,B) ((A)<(B))?(A):(B)
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