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I have the following input,
OK SYS 10 LEN 20 12 43 1233a.fdads.txt,23 /data/a11134/a.txt 3232b.ddsss.txt,32 /data/d13f11/b.txt 3452d.dsasa.txt,1234 /data/c13af4/f.txt . And I'd like to extract all of the input except the line containing "OK SYS 10 LEN 20" and the last line which contains a single "." (dot). That is, I want to extract the following
1233a.fdads.txt,23 /data/a11134/a.txt 3232b.ddsss.txt,32 /data/d13f11/b.txt 3452d.dsasa.txt.1234 /data/c13af4/f.txt I tried the following,
for item in output: matchObj = re.search("^(?!OK) | ^(?!\\.)", item) if matchObj: print "got item " + item but it does not work, as it does not produce any output.
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Not Equal Operator in Python If the values compared are equal, then a value of true is returned. If the values compared are not equal, then a value of false is returned. != is the symbol we use for the not equal operator.
Introducing Python structural pattern matching The match/case statement follows the same basic outline as switch/case . It takes an object, tests the object against one or more match patterns, and takes an action if it finds a match. Each case statement is followed by a pattern to match against.
The ?! n quantifier matches any string that is not followed by a specific string n.
Python regex re.search() method looks for occurrences of the regex pattern inside the entire target string and returns the corresponding Match Object instance where the match found. The re.search() returns only the first match to the pattern from the target string.
See it in action:
matchObj = re.search("^(?!OK|\\.).*", item) Don't forget to put .* after negative look-ahead, otherwise you couldn't get any match ;-)
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Use a negative match. (Also note that whitespace is significant, by default, inside a regex so don't space things out. Alternatively, use re.VERBOSE.)
for item in output: matchObj = re.search("^(OK|\\.)", item) if not matchObj: print "got item " + item If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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