I have a list of tuples that look like :
CODES = ( ('apple', 'reddelicious'), ('caramel', 'sweetsticky'), ('banana', 'yellowfruit'), )
What's the best way to check if a value exists in that tuple? For example I want to be able to say:
'apple' in CODES
and get True
Method #1 : Using any() any function is used to perform this task. It just tests one by one if the element is present as the tuple element. If the element is present, true is returned else false is returned.
in operator can be used to check for the membership of any element in a sequence. And don't name your tuple as tuple .
In the majority of programming languages when you need to access a nested data type (such as arrays, lists, or tuples), you append the brackets to get to the innermost item.
You are looking for any()
:
if any('apple' in code for code in CODES): ...
Combined with a simple generator expression, this does the task. The generator expression takes each tuple and yields True
if it is contains 'apple'
. any()
then returns True
when the first item it requests returns True
(otherwise, False
). Hence this does what you want. It also reads nicely - if any of the tuples contain 'apple'
.
If you are doing this a massive number of times and need performance, then it might be worth making a set of all of the values to allow you to do this very quickly:
cache = set(itertools.chain.from_iterable(CODES)))
Naturally, constructing this will be slow and use memory, so it wouldn't be a good idea unless you need a lot of performance and will be doing a lot of membership checks.
You can use itertools.chain()
:
Using it with in
will result in short-circuiting, similar to any()
.
In [30]: CODES = ( ....: ('apple', 'reddelicious'), ....: ('caramel', 'sweetsticky'), ....: ('banana', 'yellowfruit'), ....: ) In [31]: from itertools import chain In [32]: 'apple' in chain(*CODES) Out[32]: True In [33]: 'foo' in chain(*CODES) Out[33]: False
For performance comparisons you can check my other answer.
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