I'm studying ASM 8086 theoretically on highschool.
And when I do this:
MOV BX,[SI]
is SI+1 going to BH or BL?
Thank you :-)
The byte at memory location SI + 1
will be stored in the register BH
because x86 is little endian.
I think your question is about the endianness of x86, and the answer is that it is little-endian: the byte at address SI goes to BL. The byte at SI+1 goes to BH.
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