Listing defined functions in Bash

Question

I'm trying to write some code in bash which uses introspection to select the appropriate function to call.

Determining the candidates requires knowing which functions are defined. It's easy to list defined variables in bash using only parameter expansion:

$ prefix_foo="one"
$ prefix_bar="two"
$ echo "${!prefix_*}"
prefix_bar prefix_foo

However, doing this for functions appears to require filtering the output of set -- a much more haphazard approach.

Is there a Right Way?

Answer 1

How about compgen:

compgen -A function   # compgen is a shell builtin

Answer 2

$ declare -F
declare -f ::
declare -f _get_longopts
declare -f _longopts_func
declare -f _onexit
...

So, Jed Daniel's alias,

declare -F | cut -d" " -f3

cuts on a space and echos the 3rd field:

$ declare -F | cut -d" " -f3
::
_get_longopts
_longopts_func
_onexit