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I'm trying to write some code in bash which uses introspection to select the appropriate function to call.
Determining the candidates requires knowing which functions are defined. It's easy to list defined variables in bash using only parameter expansion:
$ prefix_foo="one"
$ prefix_bar="two"
$ echo "${!prefix_*}"
prefix_bar prefix_foo
However, doing this for functions appears to require filtering the output of set -- a much more haphazard approach.
Is there a Right Way?
508
Typically bash functions are permanently stored in a bash start-up script. System-wide start-up scripts: /etc/profile for login shells, and /etc/bashrc for interactive shells.
The -F option to declare will list the function names only (and optionally the source file and line number).
Defining Bash FunctionsFunctions may be declared in two different formats: The first format starts with the function name, followed by parentheses. This is the preferred and more used format. The second format starts with the reserved word function , followed by the function name.
How about compgen:
compgen -A function # compgen is a shell builtin
$ declare -F
declare -f ::
declare -f _get_longopts
declare -f _longopts_func
declare -f _onexit
...
So, Jed Daniel's alias,
declare -F | cut -d" " -f3
cuts on a space and echos the 3rd field:
$ declare -F | cut -d" " -f3
::
_get_longopts
_longopts_func
_onexit
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