In Python, I only want to list all the files in the current directory ONLY. I do not want files listed from any sub directory or parent.
There do seem to be similar solutions out there, but they don't seem to work for me. Here's my code snippet:
import os
for subdir, dirs, files in os.walk('./'):
for file in files:
do some stuff
print file
Let's suppose I have 2 files, holygrail.py and Tim inside my current directory. I have a folder as well and it contains two files - let's call them Arthur and Lancelot - inside it. When I run the script, this is what I get:
holygrail.py
Tim
Arthur
Lancelot
I am happy with holygrail.py and Tim. But the two files, Arthur and Lancelot, I do not want listed.
Linux or UNIX-like system use the ls command to list files and directories. However, ls does not have an option to list only directories. You can use combination of ls command, find command, and grep command to list directory names only. You can use the find command too.
Open the command-line shell and write the 'ls” command to list only directories. The output will show only the directories but not the files. To show the list of all files and folders in a Linux system, try the “ls” command along with the flag '-a” as shown below.
You can use the DIR command by itself (just type “dir” at the Command Prompt) to list the files and folders in the current directory.
Just use os.listdir
and os.path.isfile
instead of os.walk
.
Example:
import os
files = [f for f in os.listdir('.') if os.path.isfile(f)]
for f in files:
# do something
But be careful while applying this to other directory, like
files = [f for f in os.listdir(somedir) if os.path.isfile(f)]
which would not work because f
is not a full path but relative to the current directory.
Therefore, for filtering on another directory, do os.path.isfile(os.path.join(somedir, f))
(Thanks Causality for the hint)
You can use os.listdir
for this purpose. If you only want files and not directories, you can filter the results using os.path.isfile
.
example:
files = os.listdir(os.curdir) #files and directories
or
files = filter(os.path.isfile, os.listdir( os.curdir ) ) # files only
files = [ f for f in os.listdir( os.curdir ) if os.path.isfile(f) ] #list comprehension version.
You can use os.scandir()
. New function in stdlib starts from Python 3.5.
import os
for entry in os.scandir('.'):
if entry.is_file():
print(entry.name)
Faster than os.listdir()
. os.walk()
implements os.scandir()
.
import os
destdir = '/var/tmp/testdir'
files = [ f for f in os.listdir(destdir) if os.path.isfile(os.path.join(destdir,f)) ]
You can use the pathlib
module.
from pathlib import Path
x = Path('./')
print(list(filter(lambda y:y.is_file(), x.iterdir())))
this can be done with os.walk()
python 3.5.2 tested;
import os
for root, dirs, files in os.walk('.', topdown=True):
dirs.clear() #with topdown true, this will prevent walk from going into subs
for file in files:
#do some stuff
print(file)
remove the dirs.clear() line and the files in sub folders are included again.
update with references;
os.walk documented here and talks about the triple list being created and topdown effects.
.clear() documented here for emptying a list
so by clearing the relevant list from os.walk you can effect its result to your needs.
import os
for subdir, dirs, files in os.walk('./'):
for file in files:
do some stuff
print file
You can improve this code with del dirs[:]
which will be like following .
import os
for subdir, dirs, files in os.walk('./'):
del dirs[:]
for file in files:
do some stuff
print file
Or even better if you could point os.walk with current working directory .
import os
cwd = os.getcwd()
for subdir, dirs, files in os.walk(cwd, topdown=True):
del dirs[:] # remove the sub directories.
for file in files:
do some stuff
print file
instead of os.walk
, just use os.listdir
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