How can I specify the function type in my type hints?

Question

As @jonrsharpe noted in a comment, this can be done with typing.Callable:

from typing import AnyStr, Callable

def my_function(name: AnyStr, func: Callable) -> None:

Issue is, Callable on it's own is translated to Callable[..., Any] which means:

A callable takes any number of/type of arguments and returns a value of any type. In most cases, this isn't what you want since you'll allow pretty much any function to be passed. You want the function parameters and return types to be hinted too.

That's why many types in typing have been overloaded to support sub-scripting which denotes these extra types. So if, for example, you had a function sum that takes two ints and returns an int:

def sum(a: int, b: int) -> int: return a+b

Your annotation for it would be:

Callable[[int, int], int]

that is, the parameters are sub-scripted in the outer subscription with the return type as the second element in the outer subscription. In general:

Callable[[ParamType1, ParamType2, .., ParamTypeN], ReturnType]

Another interesting point to note is that you can use the built in function type() to get the type of a built in function and use that. So you could have

def f(my_function: type(abs)) -> int:
    return my_function(100)

Or something of that form

An easiest and fancy solution is:

def f(my_function: type(lambda x: None)):
    return my_function()

This can be proved in the following way:

def poww(num1, num2):
    return num1**num2
    
print(type(lambda x: None) == type(poww))

and the output will be: True