How to construct two regex patterns into one?
For example I have one long pattern and one smaller, I need to put smaller one in front of long one.
var pattern1 = ':\(|:=\(|:-\(';
var pattern2 = ':\(|:=\(|:-\(|:\(|:=\(|:-\('
str.match('/'+pattern1+'|'+pattern2+'/gi');
This doesn't work. When I'm concatenating strings, all slashes are gone.
You have to use RegExp
:
str.match(new RegExp(pattern1+'|'+pattern2, 'gi'));
When I'm concatenating strings, all slashes are gone.
If you have a backslash in your pattern to escape a special regex character, (like \(
), you have to use two backslashes in the string (because \
is the escape character in a string): new RegExp('\\(')
would be the same as /\(/
.
So your patterns have to become:
var pattern1 = ':\\(|:=\\(|:-\\(';
var pattern2 = ':\\(|:=\\(|:-\\(|:\\(|:=\\(|:-\\(';
Use the below:
var regEx = new RegExp(pattern1+'|'+pattern2, 'gi');
str.match(regEx);
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