The in_array() function is an inbuilt function in PHP that is used to check whether a given value exists in an array or not. It returns TRUE if the given value is found in the given array, and FALSE otherwise.
JavaScript Array includes() The includes() method returns true if an array contains a specified value. The includes() method returns false if the value is not found. The includes() method is case sensitive.
in_array() function is utilized to determine if specific value exists in an array. It works fine for one dimensional numeric and associative arrays.
No, it doesn't have one. For this reason most popular libraries come with one in their utility packages. Check out jQuery's inArray and Prototype's Array.indexOf for examples.
jQuery's implementation of it is as simple as you might expect:
function inArray(needle, haystack) {
var length = haystack.length;
for(var i = 0; i < length; i++) {
if(haystack[i] == needle) return true;
}
return false;
}
If you are dealing with a sane amount of array elements the above will do the trick nicely.
EDIT: Whoops. I didn't even notice you wanted to see if an array was inside another. According to the PHP documentation this is the expected behavior of PHP's in_array
:
$a = array(array('p', 'h'), array('p', 'r'), 'o');
if (in_array(array('p', 'h'), $a)) {
echo "'ph' was found\n";
}
if (in_array(array('f', 'i'), $a)) {
echo "'fi' was found\n";
}
if (in_array('o', $a)) {
echo "'o' was found\n";
}
// Output:
// 'ph' was found
// 'o' was found
The code posted by Chris and Alex does not follow this behavior. Alex's is the official version of Prototype's indexOf, and Chris's is more like PHP's array_intersect
. This does what you want:
function arrayCompare(a1, a2) {
if (a1.length != a2.length) return false;
var length = a2.length;
for (var i = 0; i < length; i++) {
if (a1[i] !== a2[i]) return false;
}
return true;
}
function inArray(needle, haystack) {
var length = haystack.length;
for(var i = 0; i < length; i++) {
if(typeof haystack[i] == 'object') {
if(arrayCompare(haystack[i], needle)) return true;
} else {
if(haystack[i] == needle) return true;
}
}
return false;
}
And this my test of the above on it:
var a = [['p','h'],['p','r'],'o'];
if(inArray(['p','h'], a)) {
alert('ph was found');
}
if(inArray(['f','i'], a)) {
alert('fi was found');
}
if(inArray('o', a)) {
alert('o was found');
}
// Results:
// alerts 'ph' was found
// alerts 'o' was found
Note that I intentionally did not extend the Array prototype as it is generally a bad idea to do so.
There is now Array.prototype.includes
:
The includes() method determines whether an array includes a certain element, returning true or false as appropriate.
var a = [1, 2, 3];
a.includes(2); // true
a.includes(4); // false
Syntax
arr.includes(searchElement)
arr.includes(searchElement, fromIndex)
Array.indexOf
was introduced in JavaScript 1.6, but it is not supported in older browsers. Thankfully the chaps over at Mozilla have done all the hard work for you, and provided you with this for compatibility:
if (!Array.prototype.indexOf)
{
Array.prototype.indexOf = function(elt /*, from*/)
{
var len = this.length >>> 0;
var from = Number(arguments[1]) || 0;
from = (from < 0)
? Math.ceil(from)
: Math.floor(from);
if (from < 0)
from += len;
for (; from < len; from++)
{
if (from in this &&
this[from] === elt)
return from;
}
return -1;
};
}
There are even some handy usage snippets for your scripting pleasure.
PHP way:
if (in_array('a', ['a', 'b', 'c'])) {
// do something if true
}
My solution in JS:
if (['a', 'b', 'c'].includes('a')) {
// do something if true
}
If the indexes are not in sequence, or if the indexes are not consecutive, the code in the other solutions listed here will break. A solution that would work somewhat better might be:
function in_array(needle, haystack) {
for(var i in haystack) {
if(haystack[i] == needle) return true;
}
return false;
}
And, as a bonus, here's the equivalent to PHP's array_search (for finding the key of the element in the array:
function array_search(needle, haystack) {
for(var i in haystack) {
if(haystack[i] == needle) return i;
}
return false;
}
You can simply use the "includes" function as explained in this lesson on w3schools
it looks like
let myArray = ['Kevin', 'Bob', 'Stuart'];
if( myArray.includes('Kevin'))
console.log('Kevin is here');
There is a project called Locutus, it implements PHP functions in Javascript and in_array() is included, you can use it exactly as you use in PHP.
Examples of use:
in_array('van', myArray);
in_array(1, otherArray, true); // Forcing strict type
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