Since Nothing >>= f = Nothing
for every f
, the following trivial definition is suitable for mfix
:
mfix _ = Nothing
But this has no practical use, so we have the following nontotal definition:
mfix f = let a = f (unJust a) in a where
unJust (Just x) = x
unJust Nothing = errorWithoutStackTrace "mfix Maybe: Nothing"
It would be nice if mfix f
returned Nothing
if this let
-clause wouldn't halt. (For example, f = Just . (1+)
)
Is this impossible because the Halting Problem is unsolvable?
One of the MonadFix
laws says that the monadic fixpoint must coincide with the pure fixpoint when the monadic action is pure:
mfix (return . f) = return (fix f)
Because of this, the following is required:
mfix (Just . (1+)) = mfix (return . (1+))
= return (fix (1+))
= Just (fix (1+))
And fix (1+)
is indeed bottom. So for your proposed function, the laws specify exactly how mfix
must behave (and it does behave this way).
Independently of whether the instance is law-abiding, we can ask whether we like the laws, or perhaps whether it might be useful to have another function, with a different name and different laws, that behaves as you propose; e.g. in particular these two calls should behave like this:
mfix' (Just . (1+)) = Nothing
mfix' (Just . const 1) = Just 1
This is impossible to implement for exactly the reason you say: the halting problem tells us that it's not possible to know for sure whether fix f
will loop or finish for arbitrary f
. We can approximate this function in a variety of ways, but all will eventually fall short of perfection in this regard.
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