Is (a|b)*
the same as a*|b*
? In other words, does (a|b)*
accept string which are combinations of a
s and b
s?
Is
(a|b)*
the same asa*|b*
?
They are not the same.
a*|b*
means "(0 or more a
s) or (0 or more b
s)"
(a|b)*
means "0 or more (a
or b
)s"
So, for example, ab
will be matched by (a|b)*
but not by a*|b*
. Note also that anything matched by a*|b*
will also be matched by (a|b)*
.
No.
In case of (a|b)*
, you can mix A
s and B
s (see demo).
In case of a*|b*
, you can have either A
s or B
s (see demo).
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