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inline definition causes unresolved symbols in program [duplicate]

Tags:

c

c99

I defined my function in .c (without header declaration) as here:

inline int func(int i) {
 return i+1;
}

Then in the same file below I use it:

...
i = func(i);

And during the linking I got "undefined reference to 'func'". Why?

like image 371
user14416 Avatar asked Apr 26 '13 21:04

user14416


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What causes unresolved external symbol?

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3 Answers

The inline model in C99 is a bit different than most people think, and in particular different from the one used by C++

inline is only a hint such that the compiler doesn't complain about doubly defined symbols. It doesn't guarantee that a function is inlined, nor actually that a symbol is generated, if it is needed. To force the generation of a symbol you'd have to add a sort of instantiation after the inline definition:

int func(int i);

Usually you'd have the inline definition in a header file, that is then included in several .c files (compilation units). And you'd only have the above line in exactly one of the compilation units. You probably only see the problem that you have because you are not using optimization for your compiler run.

So, your use case of having the inline in the .c file doesn't make much sense, better just use static for that, even an additional inline doesn't buy you much.

like image 51
Jens Gustedt Avatar answered Oct 04 '22 23:10

Jens Gustedt


C99 inline semantics are often misunderstood. The inline specifier serves two purposes:

First, as a compiler hint in case of static inline and extern inline declarations. Semantics remain unchanged if you remove the specifier.

Second, in case of raw inline (ie without static or extern) to provide an inline definition as an alternative to an external one, which has to be present in a different translation unit. Not providing the external one is undefined behaviour, which will normally manifest as linking failure.

This is particularly useful if you want to put a function into a shared library, but also make the function body available for optimization (eg inlining or specialization). Assuming a sufficiently smart compiler, this allows you to recover many of the benefits of C++ templates without having to jump through preprocessor hoops.

Note that it's a bit more messy than I described here as having another file scope non-inline external declaration will trigger the first case as described in Jens' answer, even if the definition itself is inline instead of extern inline. This is by design so you can have have a single inline definition in a header file, which you can include into the source file that provides the external one by adding a single line for the external declaration.

like image 24
Christoph Avatar answered Oct 04 '22 21:10

Christoph


This is because of the way GCC handle inline function. GCC performs inline substitution as the part of optimization.

To remove this error use static before inline. Using static keyword force the compiler to inline this function, which makes the program compile successfully.

static inline int func(int i) {
 return i+1;
}
...
i = func(i);
like image 23
Niloy Rashid Avatar answered Oct 04 '22 21:10

Niloy Rashid