How can one achieve what the following code is trying to do?
#include "dir/*"
If the referenced object is a folder, the function will return the parent folder of that folder. For the current folder of the current file, use $current = dirname(__FILE__); . For a parent folder of the current folder, simply use $parent = dirname(__DIR__); .
You can use opendir / readdir / closedir. Sample code which searches a directory for entry ``name'' is: len = strlen(name); dirp = opendir("."); while ((dp = readdir(dirp)) !=
PHP using scandir() to find folders in a directory The scandir function is an inbuilt function that returns an array of files and directories of a specific directory. It lists the files and directories present inside the path specified by the user.
In Bash:
HEADER=all_headers.h echo "#ifndef __ALL_HEADERS__" > $HEADER echo "#define __ALL_HEADERS__" >> $HEADER for file in dir/*.h do echo "#include <$file>" >> $HEADER done echo "#endif" >> $HEADER
You can't, without running a script beforehand that generates all #include statements.
The preprocessor can only handle one file per #include statement, so it requires an actual #include for every single file you wish to be included in preprocessing.
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