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With linq I would
var top5 = array.Take(5); How to do this with Python?
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To get the first N elements of a list, use for loop with range(0, N), create a new empty list, and append the elements of source list to new list in the for loop. range(0, N) iterates from 0 to N-1, insteps of 1.
You need to call next() or loop through the generator object to access the values produced by the generator expression. When there isn't the next value in the generator object, a StopIteration exception is thrown. A for loop can be used to iterate the generator object.
Using the * Operator The * operator can also be used to repeat elements of a list. When we multiply a list with any number using the * operator, it repeats the elements of the given list.
Iterators and generators can't normally be sliced, because no information is known about their length (and they don't implement indexing). The result of islice() is an iterator that produces the desired slice items, but it does this by consuming and discarding all of the items up to the starting slice index.
top5 = array[:5] array[start:stop:step] array[start:], array[:stop], array[::step] import itertools top5 = itertools.islice(my_list, 5) # grab the first five elements You can't slice a generator directly in Python. itertools.islice() will wrap an object in a new slicing generator using the syntax itertools.islice(generator, start, stop, step)
Remember, slicing a generator will exhaust it partially. If you want to keep the entire generator intact, perhaps turn it into a tuple or list first, like: result = tuple(generator)
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import itertools top5 = itertools.islice(array, 5) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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