How do you express an integer as a binary number with Python literals?
I was easily able to find the answer for hex:
>>> 0x12AF 4783 >>> 0x100 256
and octal:
>>> 01267 695 >>> 0100 64
How do you use literals to express binary in Python?
Summary of Answers
int('01010101111',2)
but not with a literal.0b1100111
or 0B1100111
.0o27
or 0O27
(second character is the letter O) to represent an octal.027
syntax for octals.Binary literals can be written in one of the following formats: b'value' , B'value' or 0bvalue , where value is a string composed by 0 and 1 digits. Binary literals are interpreted as binary strings, and is convenient to represent VARBINARY, BINARY or BIT values. To convert a binary literal into an integer, just add 0.
To assign value in binary format to a variable, we use the 0b suffix. It tells the compiler that the value (suffixed with 0b) is a binary value and assigns it to the variable. Note: To print value in binary format, we use bin() function.
"Binary" files are any files where the format isn't made up of readable characters. Binary files can range from image files like JPEGs or GIFs, audio files like MP3s or binary document formats like Word or PDF. In Python, files are opened in text mode by default.
For reference—future Python possibilities:
Starting with Python 2.6 you can express binary literals using the prefix 0b or 0B:
>>> 0b101111 47
You can also use the new bin function to get the binary representation of a number:
>>> bin(173) '0b10101101'
Development version of the documentation: What's New in Python 2.6
>>> print int('01010101111',2) 687 >>> print int('11111111',2) 255
Another way.
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