Suppose I have a dataframe with columns a
, b
and c
, I want to sort the dataframe by column b
in ascending order, and by column c
in descending order, how do I do this?
Sort a pandas DataFrame by the values of one or more columns. Use the ascending parameter to change the sort order. Sort a DataFrame by its index using . sort_index()
All of the sorting methods available in Pandas fall under the following three categories: Sorting by index labels; Sorting by column values; Sorting by a combination of index labels and column values.
To group Pandas dataframe, we use groupby(). To sort grouped dataframe in ascending or descending order, use sort_values(). The size() method is used to get the dataframe size.
As of the 0.17.0 release, the sort
method was deprecated in favor of sort_values
. sort
was completely removed in the 0.20.0 release. The arguments (and results) remain the same:
df.sort_values(['a', 'b'], ascending=[True, False])
You can use the ascending argument of sort
:
df.sort(['a', 'b'], ascending=[True, False])
For example:
In [11]: df1 = pd.DataFrame(np.random.randint(1, 5, (10,2)), columns=['a','b']) In [12]: df1.sort(['a', 'b'], ascending=[True, False]) Out[12]: a b 2 1 4 7 1 3 1 1 2 3 1 2 4 3 2 6 4 4 0 4 3 9 4 3 5 4 1 8 4 1
As commented by @renadeen
Sort isn't in place by default! So you should assign result of the sort method to a variable or add inplace=True to method call.
that is, if you want to reuse df1 as a sorted DataFrame:
df1 = df1.sort(['a', 'b'], ascending=[True, False])
or
df1.sort(['a', 'b'], ascending=[True, False], inplace=True)
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