How to overload __init__ method based on argument type?

Question

Let's say I have a class that has a member called data which is a list.

I want to be able to initialize the class with, for example, a filename (which contains data to initialize the list) or with an actual list.

What's your technique for doing this?

Do you just check the type by looking at __class__?

Is there some trick I might be missing?

I'm used to C++ where overloading by argument type is easy.

Answer 1

A much neater way to get 'alternate constructors' is to use classmethods. For instance:

>>> class MyData: ...     def __init__(self, data): ...         "Initialize MyData from a sequence" ...         self.data = data ...      ...     @classmethod ...     def fromfilename(cls, filename): ...         "Initialize MyData from a file" ...         data = open(filename).readlines() ...         return cls(data) ...      ...     @classmethod ...     def fromdict(cls, datadict): ...         "Initialize MyData from a dict's items" ...         return cls(datadict.items()) ...  >>> MyData([1, 2, 3]).data [1, 2, 3] >>> MyData.fromfilename("/tmp/foobar").data ['foo\n', 'bar\n', 'baz\n'] >>> MyData.fromdict({"spam": "ham"}).data [('spam', 'ham')] 

The reason it's neater is that there is no doubt about what type is expected, and you aren't forced to guess at what the caller intended for you to do with the datatype it gave you. The problem with isinstance(x, basestring) is that there is no way for the caller to tell you, for instance, that even though the type is not a basestring, you should treat it as a string (and not another sequence.) And perhaps the caller would like to use the same type for different purposes, sometimes as a single item, and sometimes as a sequence of items. Being explicit takes all doubt away and leads to more robust and clearer code.