I am having trouble remembering which one of the parameter expansions ${var%subst}
or ${var#subst}
remove from the front and which one from the back of the string. Example:
$ var=/a/b/c
$ echo dirname=${var#/*} filename=${var%%*/}
dirname=a/b/c filename=/a/b/c # Wrong!
$ echo dirname=${var%/*} filename=${var##*/}
dirname=/a/b filename=c
I always mix them and either end up writing some test commands or checking the manual. It's easy to remember that %%
removes more then %
, because %%
is a longer string then %
, 2 characters vs 1 character, same for ##
vs #
. But I always mix %
with #
.
Is there a memory rule to know which %
or #
remove from which end of the string?
Percent symbols %
always come last in numbers (e.g. 86%
), so they remove from the end.
The hash symbols #
start comments, so they remove from the start.
Remember only 1 and other will be Opposite of it.
#
Shebang starts from a hash which means it will remove from starting till pattern, if you remember this and you know what other does IMHO :)
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With