Using Wildcards with 'rename'

Question

I have been using the rename command to batch rename files. Up to now, I have had files like:

2010.306.18.08.11.0000.BO.ADM..BHZ.SAC
2010.306.18.08.11.0000.BO.AMM..BHZ.SAC
2010.306.18.08.11.0000.BO.ASI..BHE.SAC
2010.306.18.08.11.0000.BO.ASI..BHZ.SAC

and using rename 2010.306.18.08.11.0000.BO. "" * and rename .. _. * I have reduced them to:

ADM_.BHZ.SAC
AMM_.BHZ.SAC
ASI_.BHE.SAC
ASI_.BHZ.SAC

which is exactly what I want. A bit clumsy, I guess, but it works. The problem occurs now that I have files like:

2010.306.18.06.12.8195.TW.MASB..BHE.SAC
2010.306.18.06.14.7695.TW.CHGB..BHN.SAC
2010.306.18.06.24.4195.TW.NNSB..BHZ.SAC
2010.306.18.06.25.0695.TW.SSLB..BHZ.SAC

which exist in the same folder. I have been trying to get the similar results to above using wildcards in the rename command eg. rename 2010.306.18.*.*.*.*. "" but this appends the first appearance of 2010.306.18.*.*.*.*. to the beginning of all the other files - clearly not what I'm after, such that I get:

2010.306.18.06.12.8195.TW.MASB..BHE.SAC
2010.306.18.06.12.8195.TW.MASB..BHE.SAC2010.306.18.06.14.7695.TW.CHGB..BHN.SAC
2010.306.18.06.12.8195.TW.MASB..BHE.SAC2010.306.18.06.24.4195.TW.NNSB..BHZ.SAC
2010.306.18.06.12.8195.TW.MASB..BHE.SAC2010.306.18.06.25.0695.TW.SSLB..BHZ.SAC

I guess I am not understanding a fairly fundamental principal of wildcards here so, can someone please explain why this doesn't work and what I can do to get the desired result (preferably using rename).

---

N.B.

To clarify, the output wants to be:

ADM_.BHZ.SAC
AMM_.BHZ.SAC
ASI_.BHE.SAC
ASI_.BHZ.SAC
MASB.BHE.SAC
CHGB.BHN.SAC
NNSB.BHZ.SAC
SSLB.BHZ.SAC

Answer 1

You can try this first to see what commands would be executed

for f in *; do echo mv $f `echo $f | sed 's/2010.*.TW.//'` ; done

If it's what you expect, you can remove echo from the command to execute

for f in *; do mv $f `echo $f | sed 's/2010.*.TW.//'` ; done