How to print third column to last column?

Question

awk '{for(i=3;i<=NF;++i)print $i}' 

...or a simpler solution: cut -f 3- INPUTFILE just add the correct delimiter (-d) and you got the same effect.

awk '{ print substr($0, index($0,$3)) }'

solution found here:
http://www.linuxquestions.org/questions/linux-newbie-8/awk-print-field-to-end-and-character-count-179078/

Jonathan Feinberg's answer prints each field on a separate line. You could use printf to rebuild the record for output on the same line, but you can also just move the fields a jump to the left.

awk '{for (i=1; i<=NF-2; i++) $i = $(i+2); NF-=2; print}' logfile

awk '{$1=$2=$3=""}1' file

NB: this method will leave "blanks" in 1,2,3 fields but not a problem if you just want to look at output.

If you want to print the columns after the 3rd for example in the same line, you can use:

awk '{for(i=3; i<=NF; ++i) printf "%s ", $i; print ""}'

For example:

Mar 09:39 20180301_123131.jpg
Mar 13:28 20180301_124304.jpg
Mar 13:35 20180301_124358.jpg
Feb 09:45 Cisco_WebEx_Add-On.dmg
Feb 12:49 Docker.dmg
Feb 09:04 Grammarly.dmg
Feb 09:20 Payslip 10459 %2828-02-2018%29.pdf

It will print:

20180301_123131.jpg
20180301_124304.jpg
20180301_124358.jpg
Cisco_WebEx_Add-On.dmg
Docker.dmg
Grammarly.dmg
Payslip 10459 %2828-02-2018%29.pdf

As we can see, the payslip even with space, shows in the correct line.