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How to extract links from a webpage using lxml, XPath and Python?

I've got this xpath query:

/html/body//tbody/tr[*]/td[*]/a[@title]/@href

It extracts all the links with the title attribute - and gives the href in FireFox's Xpath checker add-on.

However, I cannot seem to use it with lxml.

from lxml import etree
parsedPage = etree.HTML(page) # Create parse tree from valid page.

# Xpath query
hyperlinks = parsedPage.xpath("/html/body//tbody/tr[*]/td[*]/a[@title]/@href") 
for x in hyperlinks:
    print x # Print links in <a> tags, containing the title attribute

This produces no result from lxml (empty list).

How would one grab the href text (link) of a hyperlink containing the attribute title with lxml under Python?

like image 636
torger Avatar asked Jan 18 '10 08:01

torger


1 Answers

I was able to make it work with the following code:

from lxml import html, etree
from StringIO import StringIO

html_string = '''<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
   "http://www.w3.org/TR/html4/loose.dtd">

<html lang="en">
<head/>
<body>
    <table border="1">
      <tbody>
        <tr>
          <td><a href="http://stackoverflow.com/foobar" title="Foobar">A link</a></td>
        </tr>
        <tr>
          <td><a href="http://stackoverflow.com/baz" title="Baz">Another link</a></td>
        </tr>
      </tbody>
    </table>
</body>
</html>'''

tree = etree.parse(StringIO(html_string))
print tree.xpath('/html/body//tbody/tr/td/a[@title]/@href')

>>> ['http://stackoverflow.com/foobar', 'http://stackoverflow.com/baz']
like image 76
jkp Avatar answered Oct 04 '22 22:10

jkp