How to add rank column?

Question

I would like to select records and determine rank number for each similar data.

My data is as follows.

MEMBER ID | LOAN AMOUNT 
1         | 2,000.00 
2         | 1,000.00 
3         | 4,000.00
4         | 1,000.00 

The result I wanted is shown below.

RANK|MEMBER ID|LOAN AMOUNT 
1   |3        |4,000.00
2   |1        |2,000.00
3   |2        |1,000.00
3   |4        |1,000.00 

RANK is a new column. I am using MS SQL server 2008 and created a view table as shown below but it does not resulting to what is wanted.

  select rank=count(*), s1.MemberID, s1.Loan_Amount 
   from (select MemberID, Loan_Amount from vwPrintTop20Borrowers) s1
   group by s1.MemberID, s1.LOAN_AMOUNT
     order by rank, s1.Loan_amount DESC

Please help. Thanks! :)

Answer 1

Just use RANK() :

SELECT RANK() OVER(ORDER BY t.loan_amount DESC) as [rank],
       t.memeber_id,t.loan_amount
FROM YourTable t

Although this will result in gaps E.G.

RANK | AMOUNT
 1        10
 2         9
 3         8
 3         8
 5         7

To avoid that, for SQL-Server 2008+ , use DENSE_RANK()

DENSE_RANK() OVER(ORDER BY t.loan_amount DESC) as [rank]