How do you sort an array of structs in swift

Question

I have an array of a struct and I would like to be able to sort it by either of the two variables using sort() if possible

struct{     var deadline = 0     var priority = 0 } 

I looked at sort() in the documentation for the Swift programming language but it shows only simple arrays. can sort() be used or will I have to build my own?

Answer 1

Sort within the same array variable

Sort functions bellow are exactly the same, the only difference how short and expressive they are:

Full declaration:

myArr.sort { (lhs: EntryStruct, rhs: EntryStruct) -> Bool in     // you can have additional code here     return lhs.deadline < rhs.deadline } 

Shortened closure declaration:

myArr.sort { (lhs:EntryStruct, rhs:EntryStruct) in     return lhs.deadline < rhs.deadline } // ... or even: myArr.sort { (lhs, rhs) in return lhs.deadline < rhs.deadline } 

Compact closure declaration:

myArr.sort { $0.deadline < $1.deadline } 

Sort to a new array variable

Full declaration:

let newArr = myArr.sorted { (lhs: EntryStruct, rhs: EntryStruct) -> Bool in     // you can have additional code here     return lhs.deadline < rhs.deadline } 

Shortened closure declaration:

let newArr = myArr.sorted { (lhs:EntryStruct, rhs:EntryStruct) in     return lhs.deadline < rhs.deadline } // ... or even: let newArr = myArr.sorted { (lhs, rhs) in return lhs.deadline < rhs.deadline } 

Compact closure declaration:

let newArr = myArr.sorted { $0.deadline < $1.deadline }