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I have a numpy array like this:
a = [0,88,26,3,48,85,65,16,97,83,91] How can I get the values at certain index positions in ONE step? For example:
ind_pos = [1,5,7] The result should be:
[88,85,16] 
838
You can use the pop() method to remove an element from the array.
We can access elements of an array using the index operator [] . All you need do in order to access a particular element is to call the array you created. Beside the array is the index [] operator, which will have the value of the particular element's index position from a given array.
To find the position of an element in an array, you use the indexOf() method. This method returns the index of the first occurrence the element that you want to find, or -1 if the element is not found. The following illustrates the syntax of the indexOf() method.
Just index using you ind_pos
ind_pos = [1,5,7] print (a[ind_pos]) [88 85 16] In [55]: a = [0,88,26,3,48,85,65,16,97,83,91] In [56]: import numpy as np In [57]: arr = np.array(a) In [58]: ind_pos = [1,5,7] In [59]: arr[ind_pos] Out[59]: array([88, 85, 16]) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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