How do I value-initialize a Type* pointer using Type()-like syntax?

Question

Variables of built-in types can be value-initialized like this:

int var = int();

this way I get the default value of int without hardcoding the zero in my code.

However if I try to do similar stuff for a pointer:

int* ptr = int*();

the compiler (Visual C++ 10) refuses to compile that (says type int unexpected).

How do I value-initialize a pointer in similar manner?

Answer 1

Use a typedef to make a name for your pointer type:

typedef int *ip;

ip ptr = ip();

The same idea should work for other types that require more than one lexical element (word) to define the name of the type (e.g., unsigned long, long long, unsigned long long *, etc.).